Java 实例 - 链试异常

Java 实例

以下实例演示了使用多个 catch 来处理链试异常:

/*
 author by phpcodeweb.com
 Main.java
 */
public class Main{
   public static void main (String args[])throws Exception  {
      int n=20,result=0;
      try{
         result=n/0;
         System.out.println("结果为"+result);
      }
      catch(ArithmeticException ex){
         System.out.println("发算术异常: "+ex);
         try {
         throw new NumberFormatException();
         }
         catch(NumberFormatException ex1) {
            System.out.println("手动抛出链试异常 : "+ex1);
         }
      }
   }
}

以上代码运行输出结果为:

发算术异常: java.lang.ArithmeticException: / by zero
手动抛出链试异常 : java.lang.NumberFormatException

Java 实例